Day - 4 of internship at Aartronix

- Let's start the day by making a script that uses printf and read commands.   

    using pattern printing for practice from simple 1D patterns to 2D patterns:

1D patterns :

    vertical lines

    horizontal lines

*Don't take spaces lightly during Shell scripting.

Today I completed 1st day of AdventOfCode 

In first part, I just added and substracted the value because it was simpler compared to part 2.

exec 3<$"day1-input"

dial=50

password=0

while read -u 3 -r line

do

if [ "${line:0:1}" = "R" ]

then

echo case of turn right $line

dial=$((dial+((${line:1:${#line}}))))

#if [ $dial -gt 100 ] ; then ((password++)) ; echo password : $password ; fi

dial=$(($dial % 100))

echo value of dial is $dial

if [ $dial -eq 0 ] ; then ((password++)) ; echo password : $password ; fi

fi

if [ "${line:0:1}" = "L" ]

then

echo case of turn left $line

dial=$((100 + $((dial-((${line:1:${#line}}))))))

#if [ $dial -lt 100 ] ; then ((password++)) ; echo password : $password ; fi

dial=$(($dial % 100))

echo value of dial is $dial

if [ $dial -eq 0 ] ; then ((password++)) ; echo password : $password ; fi

fi

done

echo $password

In part 2, I rewrote the whole script as it needed to count every time dial came to zero.

exec 3<$"day1-input"

dial=50

password=0

while read -u 3 -r line ; do

echo movement is : $line

if [ "${line:0:1}" = "R" ] ; then

for (( i=0 ; i<${line:1:${#line}} ; i++ )) ; do

echo dial : $dial

dial=$(( (dial + 1) % 100 ))

echo dial : $dial

if [ $dial = 0 ] ; then ((password++)) ; echo password:$password ; fi

done

fi

if [ "${line:0:1}" = "L" ] ; then

for ((i=0; i<${line:1:${#line}}; i++)) ; do

echo dial : $dial

dial=$(( (dial - 1 + 100) % 100 ))

if [ $dial = 0 ] ; then ((password++)) ; echo password:$password ; fi

done

fi

done

echo $password

Started code for day-2 of Advent of code.

Tomorrow i should be able to complete day-2 and day-3.